인프런 커뮤니티 질문&답변
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지연로딩 프록시 질문입니다.
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답변 4
1
0
^^
System.out.println(""... )에서 다음 부분을 호출하기 때문에 그렇습니다. 해당 데이터가 필요하겠지요^^?
@Override
public String toString() {
return "Team{" +
"id=" + id +
", name='" + name + '\'' +
'}';
}
0
member entitiy 코드입니다
@Entity
public class Member {
@Id @GeneratedValue
private Long id;
private String username;
private int age;
@ManyToOne(fetch = LAZY)
@JoinColumn(name = "TEAM_ID")
private Team team;
@Enumerated(EnumType.STRING)
private MemberType type;
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getUsername() {
return username;
}
public void setUsername(String username) {
this.username = username;
}
public int getAge() {
return age;
}
public void setAge(int age) {
this.age = age;
}
public Team getTeam() {
return team;
}
public void setTeam(Team team) {
this.team = team;
}
public void changeTeam(Team team) {
this.team = team;
team.getMembers().add(this);
}
public MemberType getType() {
return type;
}
public void setType(MemberType type) {
this.type = type;
}
@Override
public String toString() {
return "Member{" +
"id=" + id +
", username='" + username + '\'' +
", age=" + age +
'}';
}
}
team entity 코드입니다
@Entity
public class Team {
@Id @GeneratedValue
private Long id;
private String name;
@OneToMany(mappedBy = "team")
private List<Member> members = new ArrayList<>();
public Long getId() {
return id;
}
public void setId(Long id) {
this.id = id;
}
public String getName() {
return name;
}
public void setName(String name) {
this.name = name;
}
public List<Member> getMembers() {
return members;
}
public void setMembers(List<Member> members) {
this.members = members;
}
@Override
public String toString() {
return "Team{" +
"id=" + id +
", name='" + name + '\'' +
'}';
}
}
위 코드의 로그입니다
Hibernate:
/* select
m
From
Member m */ select
member0_.id as id1_0_,
member0_.age as age2_0_,
member0_.TEAM_ID as TEAM_ID5_0_,
member0_.type as type3_0_,
member0_.username as username4_0_
from
Member member0_
Hibernate:
select
team0_.id as id1_3_0_,
team0_.name as name2_3_0_
from
Team team0_
where
team0_.id=?
member.getTeam().getName() = 팀A
member.getTeam().getName() = 팀A
Hibernate:
select
team0_.id as id1_3_0_,
team0_.name as name2_3_0_
from
Team team0_
where
team0_.id=?
member.getTeam().getName() = 팀B
위 코드의 로그입니다.
Hibernate:
/* select
m
From
Member m */ select
member0_.id as id1_0_,
member0_.age as age2_0_,
member0_.TEAM_ID as TEAM_ID5_0_,
member0_.type as type3_0_,
member0_.username as username4_0_
from
Member member0_
Hibernate:
select
team0_.id as id1_3_0_,
team0_.name as name2_3_0_
from
Team team0_
where
team0_.id=?
member.getTeam() = Team{id=1, name='팀A'}
member.getTeam() = Team{id=1, name='팀A'}
Hibernate:
select
team0_.id as id1_3_0_,
team0_.name as name2_3_0_
from
Team team0_
where
team0_.id=?
member.getTeam() = Team{id=2, name='팀B'}
0