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spring에서 Entity작성 후 [Table ' ' doesn't exist] 오류

해결된 질문

24.03.23 20:57 작성

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영화 예매 관련 Entity를 작성 후 DB확인차 실행했는데 다른 Entity는 테이블이 잘 만들어진 것을 확인할 수 있었지만 이상하게 Seat Entity만 테이블이 만들어지지 않았습니다.

 

WARN 3508 --- [Movie Ticketing] [  restartedMain] o.m.jdbc.message.server.ErrorPacket      : Error: 1146-42S02: Table 'ticketing.seat' doesn't exist
WARN 3508 --- [Movie Ticketing] [  restartedMain] o.h.t.s.i.ExceptionHandlerLoggedImpl     : GenerationTarget encountered exception accepting command : Error executing DDL "
    alter table seat 
       add constraint FKgik5885qsff01sxe7v3kqjrhx 
       foreign key (theater_id) 
       references theater (theater_id)" via JDBC [(conn=216) Table 'ticketing.seat' doesn't exist]
org.hibernate.tool.schema.spi.CommandAcceptanceException: Error executing DDL "
    alter table seat 
       add constraint FKgik5885qsff01sxe7v3kqjrhx 
       foreign key (theater_id) 
       references theater (theater_id)" via JDBC [(conn=216) Table 'ticketing.seat' doesn't exist]
at org.hibernate.tool.schema.internal.exec.GenerationTargetToDatabase.accept(GenerationTargetToDatabase.java:94) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.internal.Helper.applySqlString(Helper.java:233) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.internal.Helper.applySqlStrings(Helper.java:217) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.internal.SchemaCreatorImpl.createForeignKeys(SchemaCreatorImpl.java:303) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.internal.SchemaCreatorImpl.createFromMetadata(SchemaCreatorImpl.java:250) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.internal.SchemaCreatorImpl.performCreation(SchemaCreatorImpl.java:172) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.internal.SchemaCreatorImpl.doCreation(SchemaCreatorImpl.java:142) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.internal.SchemaCreatorImpl.doCreation(SchemaCreatorImpl.java:118) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.spi.SchemaManagementToolCoordinator.performDatabaseAction(SchemaManagementToolCoordinator.java:256) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]
	at org.hibernate.tool.schema.spi.SchemaManagementToolCoordinator.lambda$process$5(SchemaManagementToolCoordinator.java:145) ~[hibernate-core-6.4.4.Final.jar:6.4.4.Final]

application.yml은
ddl-auto.create입니다.

대소문자 구분이 문제인가 싶어 @Table(name = "seat")도 추가하고 lower_case_table_names = 1인 것도 확인했는데 똑같이 에러가 발생하더라구요

하루종일 찾아봐도 이유를 잘 모르겠습니다 왜그런걸까요 ㅠㅠㅠ

Seat Entity 코드는 아래와 같습니다.

@Entity
@Table(name = "seat")
class Seat {

    val row : String? = null
    val column : Int? = null
    //좌석 선택

    @Enumerated(EnumType.STRING)
    val selectStatus : SelectStatus? = null // POSSIBLE, IMPOSSIBLE

    @ManyToOne(fetch = FetchType.LAZY)
    @JoinColumn(name = "theater_id")
    val theater : Theater? = null

    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    @Column(name = "seat_id")
    val id : Long = 0L
}

답변 1

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juhyeonbt861님의 프로필 이미지
juhyeonbt861
질문자

2024. 03. 23. 22:09

자답입니다. 방금 해결하였는데

데이터베이스의 키워드나 예약어를 엔티티 클래스에 사용해서였습니다.

application.yml에 아래 내용을 추가하면 정상작동하네요.

  jpa:
    properties:
      hibernate: 
        globally_quoted_identifiers: true